Grade 11 → Algebra → Complex Numbers ↓
Operations with Complex Numbers
Complex numbers may seem like a difficult concept at first glance, but they are actually quite simple to understand once you understand them. In this comprehensive guide, we will explore what complex numbers are, how to perform operations with them, and provide numerous examples as well.
Understanding complex numbers
At the root of complex numbers is the imaginary unit i
, which is defined as the square root of -1. Therefore, i2 = -1
. A complex number is a number that has two parts: a real part and an imaginary part. It can be represented as:
A+ Bye
Here, a
is the real part, and bi
is the imaginary part. For example, 3 + 4i
is a complex number where 3 is the real part, and 4i
is the imaginary part.
Visual representation of complex numbers
Complex numbers can be easily visualized on the complex plane. The complex plane is similar to the Cartesian plane, where the horizontal axis (x-axis) represents the real component and the vertical axis (y-axis) represents the imaginary component.
In this diagram, the point (250, 150) represents the complex number 3 + 4i
. The x-coordinate (250) is 3 units from the imaginary axis, and the y-coordinate (150) is 4 units from the real axis.
Operations on complex numbers
Complex numbers can be added, subtracted, multiplied, and divided just like regular numbers. Let's look at each operation in detail.
Sum of complex numbers
To add two complex numbers, you just need to add their corresponding real parts and their corresponding imaginary parts. Consider the complex numbers (3 + 4i)
and (1 + 2i)
.
(3 + 4i) + (1 + 2i) = (3 + 1) + (4i + 2i) = 4 + 6i
So the sum of 3 + 4i
and 1 + 2i
is 4 + 6i
.
Subtraction of complex numbers
Subtracting complex numbers follows the same process as addition. You subtract the corresponding real parts and imaginary parts. Consider (5 + 6i)
and (2 + 3i)
.
(5 + 6i) – (2 + 3i) = (5 – 2) + (6i – 3i) = 3 + 3i
Therefore, the difference is 3 + 3i
.
Multiplication of complex numbers
To multiply complex numbers we need to use the distributive property, treating i
as a regular variable with the special rule that i2 = -1
. Let's multiply (2 + 3i)
and (4 + i)
.
(2 + 3i) * (4 + i) = 2*4 + 2*i + 3i*4 + 3i*i = 8 + 2i + 12i + 3(-1) = 8 + 14i – 3 = 5 + 14i
Hence the product of 2 + 3i
and 4 + i
is 5 + 14i
.
Division of complex numbers
Dividing complex numbers involves multiplying the numerator and denominator by the conjugate of the denominator. The conjugate of the complex number a + bi
is a - bi
.
Consider dividing (1 + 2i)
by (3 + 4i)
. First, find the conjugate of the denominator 3 + 4i
, which is 3 - 4i
, and multiply both the numerator and denominator by this conjugate.
(1 + 2i) / (3 + 4i) * (3 - 4i) / (3 - 4i) = [(1 + 2i) * (3 - 4i)] / [(3 + 4i) * (3 - 4i)]
Now, let's multiply the fractions:
(1 + 2i)(3 - 4i)
= 1*3 + 1*(-4i) + 2i*3 + 2i*(-4i)
= 3 - 4i + 6i - 8i2
= 3 + 2i + 8 (since i2 = -1
)
= 11 + 2i
Next, we multiply the denominators:
(3 + 4i)(3 - 4i)
= 3*3 + 3*(-4i) + 4i*3 + 4i*(-4i)
= 9 - 12i + 12i - 16i2
= 9 + 16 (since i2 = -1
)
= 25
Ultimately the division becomes like this:
(11 + 2i) / 25
Thus, the result of dividing 1 + 2i
by 3 + 4i
is 11/25 + (2/25)i
.
Conjugate of a complex number
The conjugate of a complex number is obtained by changing the sign of its imaginary part. If the complex number is a + bi
, then its conjugate is a - bi
. As demonstrated earlier, the conjugate plays an important role in the division of complex numbers.
Polar form of complex numbers
In addition to the standard form a + bi
, complex numbers can also be expressed in polar form, where they are represented as magnitudes and angles relative to the positive real axis. The polar form is written as:
r(cos(θ) + i sin(θ))
Here, r
is the magnitude or modulus, which is the distance from the origin to the point, and θ
(theta) is the argument, or the angle made with the positive real axis.
Example of conversion to polar form
Consider the complex number 3 + 4i
. To convert it to polar form, first find the magnitude r
:
r = √(a2 + b2) = √(32 + 42) = √(9 + 16) = √25 = 5
Next, find the angle θ
, which can be found using the arctangent function:
θ = tan-1(b/a) = tan-1(4/3)
Now, the polar form of 3 + 4i
is:
5(cos(tan-1(4/3)) + i sin(tan-1(4/3)))
Cube and higher order roots of complex numbers
Just like real numbers, complex numbers can have roots. The nth root of a complex number can be found using de Moivre's theorem, which states that for a complex number in polar form:
zn = [r(cos(θ) + i sin(θ))]n = rn(cos(nθ) + i sin(nθ))
For example, finding the cube root of 8
involves finding the roots of 8
in polar form, which are as follows:
2(cos(0 + 2πk/3) + i sin(0 + 2πk/3)) for k = 0, 1, 2
Calculate each value to get the cube root.
Conclusion
Operations with complex numbers may seem challenging at first, but they are very simple once you understand the basics. We have covered many basic operations and given many examples. Remember that practice makes perfect, and working on different problems will strengthen your understanding of complex numbers and their operations.